Note: This is an archived post that was originally sent to the Hollywood mailing list on Sun, 23 Mar 2008 18:31:47 -0000
Hi
More likely it is a space, which is ascii code 32. You can try this..
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@DISPLAY {color=#RED}
CreateTextObject(1,"\255") /* This returns character 255 */
DisplayTextObject(1,50,50)
WaitLeftMouse
End
This wil not produce any error though you cannot see anything on screen as chr(255) has no visible representation. However...
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CreateTextObject(1,"\65") will print an "A"
CreateTextObject(1,"\32") will trigger the error you mention.
As you say, since space is a regular character and the first one after all the classic control characters (numbered 0-31) my guess is the program has a check for a lower limit to character codes that filters one character code to much.
regards Jesper